How to fix pressure and force for hydraulic lift problem

With the lift in balance with equal levels of fluid, a person of mass 100 kg of salt in the car. What is the difference in height of the balance fluid levels in the pistons?

100 kg, a person gets into a car of 1600 kg mass, so it becomes a mass of 1700 kg.

The system was in equilibrium, but now increases greater mass, so it must fall.

In addition to lower weight on the piston, the mass is available to maintain the system in balance?

I understand what was written, the first part of the problem is to find the mass (weight or force) on the small piston (25 cm2), which balances with the mass of the car (1600 kg) on the piston’s largest (630 cm2) at the same height.

It is essentially a problem of static electricity. How do you solve for the initial mass of 63.5 kg?

In the second part, a person (100 kg) is added to the car for a total mass of 1700 kg. The large piston will drop and the small piston will rise to establish a new equilibrium.

So what is the new height, if it does not add extra mass to the piston small?

I remember the pressure of the fluid must be the same thing at the same height in a static situation.

Also remember Force = Pressure x Area or vice versa Pressure = Force / Area.

Here’s how I got 63.5 kg in the first part:

are in a closed cylinder … (elevators and plumbing), if I push on the plunger 1 with
F (1), increases the pressure in the cylinder by:

Change in pressure = F (1) / A (1) EQA. 1

Pascal’s principle, the pressure in the cylinder 2 increases for the same amount, so that the force F major (2) = pressure deviation x (2)

Substituting Equ. 1 in the top, and so on … I have the equation:

F (2) = (F (1) / A (1)) x A (2), … I used 25 m ^ 2 as my first piston, 6.3 m ^ 2 as my second area of the piston.

F = mg, then plug everything in and solve m (1)

I did not use gender, perhaps the same approach to solve for the second part?

The height, h, 2.3 m, is correct.

Now, solve for H, the reduction in the height of the piston of large size, one can assume an incompressible fluid, the use and conservation of mass, which implies the conservation of volume.

The volume displaced by H, H * A (where A is the piston area wide) must be equal to h, the volume of the piston of the smallest in the industry, A. However, remember the starting point is in equilibrium, which means that even if the small piston is not displaced by h above the equilibrium point, but HH. The height h is on the large piston fell H.

The volume change is measured by compliance with the elevation of the balance.