How do
1. Calculate the size cylinder

Formula for diameter

D = [(A x 4) / 3.14] 1 / 2.
D = [(22 x 4) / 3.14] 1 / 2.
D = [28.02] 1 / 2.
D = 5.29 inches.

Therefore, to use 5 inch piston-cylinder, 3-inch (5.29-inch size available in the market) and to add more pressure to get the desired strength.

From formula

F = P / A (at P = 2,000 pounds per square inch, A = 5 inches).
F = (2,000 x 3.14 x 5 x 5) / 4.
F = 39,250 lbs.
F = 17.8 tons.

2. Calculate the size of the pump.
From formula

Q = V * A.
Q1 = 3 x {[(3.14 x 5 x 5) / 4] – [(3.14 x 3 x 3) / 4]}.
Q1 = 37.7 cubic inches per second.
Q1 = (37.7 x 60) / 231.
Q1 = 9.79 gallons per minute (GPM) (231 cubic inches = 1 US.gallon).
Q1 = 9.79 / 0.2642.
Q1 = 37.05 L / min (I / min) (0.2642 US.gallon = 1 liter).

Oil flow (Q1) in the run up the piston stroke = 9.79 gallons per minute (GPM).

Q2 = 1.5 x [(3.14 x 5 x 5) / 4].
Q2 = 29.44 cubic inches per second.
Q2 = (29.44 x 60) / 231.
Q2 = 7.64 gallons per minute.

Oil flow (Q2) in the piston down stroke. (Not yet touching piece of work) = 7.64 gallons per minute.

Q3 = 0.2 x [(3.14 x 5 x 5) / 4].
Q3 = 3.92 cubic inch per second.
Q3 = (3.92 x 60) / 231.
Q3 = 1.01 gallons per minute.

Oil flow (Q3) in the piston down stroke. (When recording part) = 1.01 gallons per minute.

Therefore, a double-pump, pump size 7 gallons per minute and 1 gallon per minute at 1,200 rpm or size 8.45 gallons per minute and 1.2 gallons per minute at 1,450 rpm.

3. Calculate the magnitude of the electric motor.
From formula

Horsepower (HP) = {[Flow Rate (GPM) x Pressure (PSI)] / 1714} + Safety Factor 20%.
Horsepower (HP) = {[(8.45 + 1.2) x 500] / 1714} + 20%.
Horsepower (HP) = 3.4 hp (when the piston moving down Not reach parts).
Horsepower (HP) = {[1.2 x 2,000] / 1714} + 20%.
Horsepower (HP) = 1.7 hp (when compressed specimens).

Activity: Study and learning with simulate picture thus as below ,Understand Label prefill and decompression components. Complete sequencing of press controls .
The hydraulic press depends crucially Pascal pressure in a closed system is constant. At one end of the system, a piston is driven by a small cross-section of a lever to increase strength. Small-diameter pipe leads to the other end of the system. See the simulate picture thus as below .

Pascal’s Law: The pressure in a confined liquid is transmitted intact and acts with equal force on equal areas and 90 degrees to the vessel wall.

A liquid, as oil is displaced when the piston is pushed inward. The small piston for a given distance of movement, moves a smaller scale than the large piston, which is the ratio of the area of the piston head proportionately. Therefore, the small piston must be moved to move a large distance to the piston big to escape. The distance between the piston moves at great distance the piston moves, divided by the ratio of surface, the piston head. Thus energy is conserved in the form of work in this case and the law of conservation of energy is satisfied. Work is force multiplied by distance, and it increases with the force exerted on the piston greater the distance the force must be reduced excessively.